After setting out in the sums and collecting the terms in x^j I'm left with a series of expressions in
a_2, a_3 etc as I believe I'm supposed to. However my first expression reads
2a_{2}+2a_{1}+a_-_{1}=0
Now I'm told that
y(o) = 1 and
y'(o) = 0
I think this means that
a_0 = 1
and...
Here we are so far (can't get LaTex to work today!)
(e^x - e^-x)/2 = sinh(x)
so
2x + e^x - e^-x = 2x + 2sinh(x)
and for integration by parts
INT u.dv = uv - INT v.du
we have
u=2x+2sinh(x)
du=2+2cosh(x)
dv=sin(j*pi*x)
v=(1/j*pi)*cos(j*pi*x)
how am I going?
I wondered if someone could help me to find the Fourier series for this function please. I believe it's an odd function.
f(x) = 2x+e^x-e^-x (-1< x > 1)
This is my first post, so I'm going to try this LayTex typing too! Here goes!
f(x)=2x+e^x-e^-^x (-1< x >1)
Thanks