Here is the table with the parameters (the parameters are OK, they are not the problem).
v= 50 km/h = 14 m/s
Effective area = C(d)A= 1 m2
d = 500 m
efficiency = η= 85%
mc = 1000 kg (100kg battery) or 1100 kg (200 kg battery)
ρ = 1.3 kg/m3
100 kg battery (total mass 1000kg):
power...
I understand the calculation errors you've mentioned above, I have corrected for that. But I don't get more range for more kg battery.
If you look at the formula's more mass of car means more power needed and therefore less range, because the driving time will be less (and thus less distance).
The 500m is the distance between two stops. This is very common in the city. The car that I am talking about drives only in the city and you need to stop every 500m (traffic).
The mass of the car is 900 kg and 100 kg battery (thus 1000 kg). If the battery is 200 kg the total mass will be 1100...
Well, the problem is that if I do the same calculation with a 200 kg of battery (mass car is then 1100) then the range would be less. I don't think that this is correct, the range should be more of course.
I want to calculate the range of an Electric Vehicle (EV) with a Li-ion battery of 200 Wh/kg.
Parameters
v= 50 km/h = 14 m/s
A= 0.8 m2
d = 500 m
efficiency = η= 85%
mc = 900 kg incl. 100 kg battery
ρ = 1.3 kg/m3
First I have calculated the power of the EV with a speed of 50 km/h and...