okay given a certain speed you can calculate the stopping distance
x= [m]
v= [m/s]
a= 5 [m/s^2]
t= [s] braking time
for a certain speed you calculate braking time:
t=v/a
x=(1/2)*a*t^2
as stated above t=v/a so -> t^2=(v/a)^2.
x=(1/2)*5*(v/5)^2
x= 2.5*(v^2)/(5^2)
x=0.1*v^2
praise me!
if you substitute h [m] by hdot [m/s] (with the dot on top, meaning it's the time-derivative) then E also becomes a time derivative. That's what you want. E [J] becomes P [W] (J/s=W)
so hdot is 1.5 m/s yes yes!
iidesjo!
okay,
Fg=m*g (Fg is gravitational force)
Girl weighs (m) 62 [kg].
Gravitational constant (g) is 9.81 [m/s^2]
Fg= 62*9.81= 608.22 [N]
that is the static value.
With F=m*a you can calculate the difference in force compared to static (v=c)
a= -5 [m/s^2]
F= 62*-5= -310 [N]...