Ok so I need to change my stress formula to tau=Force/(width of the bond (D2-D1) * height of the bond)
in the first case it would be 219.9 lbf /(.005 in.*.27 in.)=162888.9 psi
I've been looking around most everything I've seen are lap joints
Homework Statement
A Solid rod with .375 in. D sits glued in the hole with .38 in. D. There is glue only on the annulus of the rod. A force is applied to the back side of the rod until the glue bond is fully sheared and the rod falls out.
Find the shear stress
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