According to R Shepard, Amateur Physics for the QAmateur Pool Player, p22, "for a given for ce on the cue stick and a given stroke length, a light cue stick will acquire the same energy as a heavy cue stick." So that's that...
When a cue ball is driven into another ball, it is either not accelerating or decelerating at impact. It has momentum but not (positive) force. What (work?) is imparted to the struck ball, and in what units of measurement?
The range is actually from 18 - 25 oz, although 18-21 is normal, and you can notice that 16.7% increase.
It is safe to assume for present purposes that the coefficient of restitution of the 5 1/2 oz ball is 1.0.
There seems to be a 2 part model. First, the cue acceleration -- a biomechanical...
Newton 2nd law -- force = mass (grams) * acceleration (miles/sec)**2. (1) I don't see how weight is involved. (2) the body/arm propelling the cue must figure in.