Recent content by binicle

hi, I'm studing momentum & impulse, i think the force exerted by the hail at time t is the force of the number of hails instantaneously exerting the roof at time t. Not all the hails in a volume V, just the hails in the surface.

actually, i don't know how many hail will exert on the roof, because 110 hails in 1m^3 doesn't say anything about the number of the hails.

i have just calculated again, V = 0.905 cm^3 and mass = 0.905 x 0.920 = 0.833 g. F = ma , but i don't know how to find acceleration of the hail? is it a = g =9.81 ? Also, where will we use v=14 m/s and 9.0 m x 20.0 m flat roof and 110 hails in 1 m^3? I can not figure out anything related...

hi, i only calculated the mass of the hail, 1cm^3 has a mass of 0.920g --> the hail has volume pi.d^3/6 = 0.905 --> the mass of hail is 1.017 Actually, i have no idea about how to calculate the force! i think F = mg , but it is wrong.

I cannot know how to calculate the force of the hail :bugeye: During a violent thunderstorm, hail the size of marbles (diameter = 1.20 cm) falls at a speed of 14.0 m/s. There are estimated to be 110.0 hailstones per cubic meter of air. Assume that, as for ice, 1.00 cm3 of hail has a mass of...