Recent content by Biru
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
im very new to this forum..so i dunt quite know how to have all those fractions and powers and stuff.. so it will take me years to write the stuff i have got scribbled on a piece of paper infront of me- Biru
- Post #26
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
Sorry abt that..i shall do it rite away..2 mins..- Biru
- Post #25
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
have i got it wrong again??- Biru
- Post #23
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
So the length decreased by 596.831 nano meters? hence the outer circle diameter increased by 11.539 nano meters..so made it...116.0000115 mm... and the inner circle diameter increased by 9.947 nano meters..so made it 100.0000099 mm.. So..the wall thickness changed by 776.4085 pico meters?? NO?- Biru
- Post #22
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
i got -61.316 KPa for bob...is that rite?? bob = force / area..- Biru
- Post #20
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
Or is it...Pi x r1 squared - Pi x r2 squared??- Biru
- Post #19
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
is it Pi/4 x ((d1^2) - (d2^2))??- Biru
- Post #18
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
umm...the only formula i kno is that.. pi x radius squared... so wat wud it be for hollow pipe?? Pi x (bigger radius - smaller raidus) squared??- Biru
- Post #16
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
well first I worked out bob = Force / Area (CSA)..soo -180kn / pi x (116mm/2)squared! got sumthing like -17.032 mega pascals... then i worked out the change in length..using.. (bob x initial length) / Elasticity so (-17.032..MPa x 1.8) / 200GPa ..got me -153.289 nano meters...so bascially when...- Biru
- Post #14
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
umm...the wall thickness changes by 204 nano meters??- Biru
- Post #12
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
so change in diameter = -0.3 x -(change in length/initial length) x initial diameter?- Biru
- Post #10
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
rite..will i have to do it for both..the outside diameter and the inside diameter?- Biru
- Post #9
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
its basically lateral strain / direct strain...the ratio between the two strains in other words...its mostly always 0.28 - 0.38... helps??- Biru
- Post #7
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
0.3 haha sorry!- Biru
- Post #5
- Forum: Introductory Physics Homework Help
-
B
How to Calculate Change in Wall Thickness Under Axial Compressive Load
physical interpretation of poisson's ratio? how do you mean?- Biru
- Post #3
- Forum: Introductory Physics Homework Help