Recent content by BlackPhysics

Yes i do. Avg F = 1.0577875 N Work = 1.0577875 N * .11M 0.11635 J = 1.0577875 N * .11M Is this right?

1.0577875 N

1.0577875 is what i got as the avg force

0.52889375 is that right?

W = 2.327 * x?

2.327? is that right?

How do you calculate that without time? average force = f = m(VI-VF)/T

F = (0.001963M^2) * 1000 kg. m^3 * 9.8 m/s^2 * (0.11m) F = 2.1166W = F * (Delta X) 0.2328J = 2.1166 * 0.11m ok so i converted cm^2 to m^2 and the force is not the buoyant force. So I am guessing its the force that is pushing the cylinder in the water?

F is the buoyancy force F = (0.1963m^2) * 1000 kg. m^3 * 9.8 m/s^2 * (0.11m) F = 192.42251

F = (0.01963m^2) * 1000 kg. m^3 * 9.8 m/s^2 * (0.11m) F = 2.1166W = F * (Delta X) 0.2328J = 2.1166 * 0.11m Does it look like this? The average force is just the mass * gravity?

im guess it would be in the center to start and after the water is displaced it has to move

yes i know calculus. Do i just take the integral of the formula?

so knowing its not constant now what? how can i calculate the Force.

it is not constant...

Work = force * distance