Recent content by blakpete91

Light bulb just went off. Thank you for all your help. That last part made a lot of sense.

Ah ok I see why it is linear independent now but I still don't understand why it wouldn't span since there is a pivot in every row.

Thank you for the quick detailed response. If what you say is true how come the following example is linearly independent if the third column does not contain a pivot? v1 = [3,1,2] v2= [-1 8 4] putting into matrix form 3 ,1 ,2 -1, 8 ,4 row echelon form 1 , 0.333, 0.666 0 , 1 , 0 .56...

Hello I'm taking linear algebra and have a couple of questions about linear independence, spanning, and basis Let me start of by sharing what I think I understand. -If I have a matrix with several vectors and I reduce it to row echelon form and I get a pivot in every column then I can assume...