Recent content by blaze33

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    Calculating Momentum and Velocity in a Head-On Car Collision

    i won't check it with a calculator, but i see u got the point. :)
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    Angular Momentum, Torque, and Acceleration for a Moving Body

    if u differentiate the velocity vector u get the acceleration vector. if u integrate the velocity vector u get the position vector. u know how integration works right?
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    Angular Momentum, Torque, and Acceleration for a Moving Body

    u get position vector by integrating the velocity vector.
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    Calculating Momentum and Velocity in a Head-On Car Collision

    u don't need to use F in this problem at all. its all about momentum. yes u can solve for the velocity of the second car using conservation of momentum: Pi = Pf m1v1 + m2v2 = m1fv1f + m2fv2f since they come to rest after collision the final momentum is 0. so m1v1 = -m2v2 i think u can...
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    Why am I getting a negative? (Energy conservation)

    lol i was stuck in the same question as well but its kinda easy and don't break ur head with this stuff.. just remember the equation u won't have time to think about it on the exam
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    Angular Velocity: Find Initial Velocity Given Acceleration & Displacement

    lol jegues thanks. hope the exam will be simpler than that haha
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    Angular Velocity: Find Initial Velocity Given Acceleration & Displacement

    Homework Statement a wheel rotates with a constant angular acceleration pie rad/s^2. during a certain time interval its angular displacement is pie rad. at the end of the interval its angular velocity is 2pie rad/s. what is the angular velocity at the beginning of the interval? Homework...
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    Limit as x approaches 1/3: (2-6x)^2 / (3x-1)(9x^2-1) | Homework Help

    yea i got it thanks! i looked at the question and did it all over again and i certainly missed that i should have done 4(3x - 1)(3x -1) instead of 4(3x +1)(3x +1) and for the final expression i got: 4(3x-1)(3x-1)/(3x-1)(3x-1)(3x+1) which gives 2 after substituting.
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    Limit as x approaches 1/3: (2-6x)^2 / (3x-1)(9x^2-1) | Homework Help

    yea i got 4(9x^2 - 6x + 1) the first time as well but didnt know what to do with it further.. I am bad at factoring i heard about l'hopital's rule but never learned how to use it.. my prof. didnt teach us because he said sometimes it doesn't give the right answer so why bother
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    Limit as x approaches 1/3: (2-6x)^2 / (3x-1)(9x^2-1) | Homework Help

    yea your right... I am not too good at algebra anyway so it takes time till i realize things like that
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    Limit as x approaches 1/3: (2-6x)^2 / (3x-1)(9x^2-1) | Homework Help

    simplifying the numerator gives 36x^2-24x+4 factor it to (12x+4)(3x+1) factor it again to 4(3x+1)(3x+1) so 4(3x+1)(3x+1)/(3x-1)(9x^2-1) can i cancel (3x+1) and (3x-1) ? well i tried canceling it anyway and then substituted 1/3 again now i get 8/0 so its +infinity i guess.
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    Limit as x approaches 1/3: (2-6x)^2 / (3x-1)(9x^2-1) | Homework Help

    Homework Statement limit as x->1/3 of (2-6x)^2/(3x-1)(9x^2-1) Homework Equations The Attempt at a Solution substituting gets 0/0, tried expanding but it doesn't work either, don't know what else is there left to do...
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