Recent content by blazin247nc

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    Fluid Mechanics - Floating Bodies

    OK, I see what I was doing wrong now. I got 600 kg/m^3 as the density of the mystery fluid. Seems like a more reasonable answer than -200 :P
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    Fluid Mechanics - Floating Bodies

    Fluid Mechanics -- Floating Bodies Homework Statement A solid block with specific gravity 0.9 floats so that 75% of the body is submerged in water and the other 25% sits in an unknown fluid layered above the water. Find the specific gravity of the unknown fluid. density of water = 1000...
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    MATLAB Error in MATLAB - Troubleshooting Guide

    [MATLAB] -- Getting Error Code: % Define variables for wn and z wn = 5; z1 = 0; z2 = 0.2; z3 = 0.9; z4 = 1; z5 = 2; z6 = 30; % Define transfer functions num = [wn^2]; den1 = [1, 2*z1*wn, wn^2]; den2 = [1, 2*z2*wn, wn^2]; den3 = [1, 2*z3*wn, wn^2]; den4 = [1, 2*z4*wn, wn^2]; den5 =...
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    Calculating Initial Speed: Soccer Player Kicks Rock Off Cliff into Water

    since the time is 2.86s then the time of the sound is .14s 343 * .14 = 48.02 48^2 - 40^2 = 704 ... 704^1/2 = 26.5 <---pythagorean theorem x(final)=26.5 x(final)=Vx(initial)*t Vx(initial)=26.5/2.86 = 9.3 The answer in the back of the book is 9.91 so maybe roundoff error?
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    Calculating Initial Speed: Soccer Player Kicks Rock Off Cliff into Water

    nm i figured it out ill post my solution in a second
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    Calculating Initial Speed: Soccer Player Kicks Rock Off Cliff into Water

    Since it is projected horizontally the angle would be 0 so the initial velocity would be equal to the intial velocity in the x direction. So from here, without the final x position I don't see how I can find the intial velocity.
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    Calculating Initial Speed: Soccer Player Kicks Rock Off Cliff into Water

    y(final)=y(initial)+Vy(initial)*t - 1/2(9.8)(t^2) -40= 0 + 0 -4.9t^2 8.16 = t^2 t = 2.86 Since it is projected horizontally the initial velocity in the y direction should be 0 as well as the initial y position, correct?
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    Calculating Initial Speed: Soccer Player Kicks Rock Off Cliff into Water

    my original work is as follows: 40/t = 343m/s t=0.117s <--- time the sound takes to relay 3-0.117= 2.88 <---- time for the rock to hit the water. HOWEVER, that is only based on the distance of the y direction and doesn't incorporate how far the rock traveled in the x direction.
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    Calculating Initial Speed: Soccer Player Kicks Rock Off Cliff into Water

    Here's a tricky one! Homework Statement A soccer player kicks a rock horizontally off a 40.0m high cliff into a pool of water. If the player hears the sound of the splash 3.00s later, what was the initial speed given to the rock? Assume the speed of sound in air to be 343 m/s. I am...
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