Recent content by blithe285

Actually but.. If the bath has a measurable temperature change because of heat exchange.. Wouldn't the system in the bomb calorimeter also have a temperature change via thermal equilibrium?? (0th Law) Ugh, I'm confusing myself even more! >_<

Thanks for the reply! However, if you are doing a combustion reaction in a bomb calorimeter and it is allowed to exchange heat energy with a bath, you can measure the temperature change of the bath, right? Hmm, actually now that I type it out, is it because the temperature of the stuff inside...

Mm. So there is also a change in temperature? We had a homework problem dealing with constant volume calorimetry, and there was a temperature change of 2.5 K and a mole-of-gas change of -1/2. However, in the solutions, the equation they used was just ΔH = q + (Δn)RT And they just used the...

When doing constant volume calorimetry, the enthalpy can be calculated as follows: ΔH = ΔU + Δ(PV) ΔH = w + q + Δ(PV) ΔH = PΔV + q + Δ(PV) and at constant volume: ΔH = q + VΔP which I've then see people rewrite using the ideal gas law as follows: ΔH = q + (Δn)RT where Δn is the change in...