Hello.
I've got a big moral dillema that I can't seem to solve myself :confused:
This is my situation: final year in uni, finishing my BSc. w/ Physics Major and Comp.Sci. minor.
My GPA is good enough to get me into a graduate program.
Over the years I've realized that I enjoy programming...
Homework Statement
We know that for dry air, we have:
-78.08% mol N2 ;
-20.94% mol O2.
This is:
- Y(N2) = 0.7808 for nitrogen (the molar fraction in vapor)
- Y (O2) = 0.2094 for oxygen
Knowing that the Henry's law constants are:
for N2 and O2 are 6.51 x 10^7 Torr and 3.3 x 10^7 Torr...
Homework Statement
Homework Equations
[PLAIN]http://img577.imageshack.us/img577/6756/physforumsquestion.png
The Attempt at a Solution
I am pretty much stuck guys. Any help will be greatly appreciated!
(4*10-4)(sin1.2) actually comes up to ~ 8.377 x 10^-6 which divided by 5.5 gives ~ 1.523 x 10 ^ - 6m or 1523 nm. Remember, you are working with degrees, not radians.
No, I don't think so. the distance between slits (a) multiplied by the sin of the angle given (sinQm) equals wavelength (landa) x (order). In this case, you are referring to dark fringes and the order gets a 1/2 added to it.
So a.sinqm=landa.(5+0.5)
comes out to be 1523 x 10^-9 m.
The equation...
I find that your solution is correct. I obtained the same result, 1523 nm for the wavelength. You never know, sometimes homework sets/ exercises in books are not 100% fine.
When I had to sketch level curves, my teacher showed me a nice and easy to understand method:
Your equation is f(x,y) = x^2 + 2y^2 . Write it as z = x^2+2y^2
which could also be re-written as z=(x^2/1)+(y^2/1/2)
Now that you have a clearer idea of what this could represent : if z=k a...
Hello. I've been struggling with this problem for some time, and honestly I do not know how to solve it.
Homework Statement
Two positive lenses are to be used as a laser beam expander. An axial 1.0 mm diameter beam enters the short focal length positive lens, which is followed by a...
Hello. I'm having some difficulty with a question from Optics (4th edition, Hecht).
http://milicioner.hit.bg/newphysicsquestion.GIF
I included the answer in the same image (it is at the end of the book), but I can't understand why (-E/(rsqr2))i must be negative.
Thank you