thank u sooo much...i knew that 15m was negative but i did not know that you had to add it to the car's velocity before using pythagoras...i thought u used pythagoras then added that quantity to the car's velocity...thanx for clearing that up...the directions make soo much more sense now! so...
hahaha ok wow...im really bad at physics...anyway about the hobo...he is moving in an opposite direction which the vector diagram shows but because each value is squared direction will always be postive...so in terms of displacement for the hobo its 16m which means that his displacement relative...
thank u sooo much i am starting to actually get this...thanx for helping me through it...o wait one last question about the plane one it goes 160km/hr and umm the direction it would have to travel is northeast right? or is it east of north...i always get confused and yes...the hobo is moving...
ok the car displacement is 62m because 2.5 m/s times 25 s and then the hobo displacement is maybe possibly either 16m or 18m so the answer could be unless i am totally wrong which of course is probable, between 78m and 80m
so obviously i didnt understand! hahaha ok i don't know if this is right either but are u solving for the hypotenuse? if u are then the plane's velocity is 150km/hr + 50km/hr both quantities squared = 25000 then the square root of that is like 158 and with sig figs 160km/hr...or do u have the...
so for the first one is the answer 200 km/hr and the second one 62m? i totally understand the first one and for the second one i understnad multiplying the velocity by the total change in time so thanx! BUT what i don't understnad is how the problem would be setup/solved differently should the...
vectors! please help no comprendo!
a pilot wishes to fly to a point 450 km due south in 3 hours. A wind is blowing from the west at 50 km/hr. draw the situation and then compute the proper heading and speed the pilot must choose to achieve this objective.
and
a hobo hops a freight car 15m...