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  1. B

    Preparing 0.3M Phosphate Buffer at pH 7.9: c), d), e), f)

    V=150 ml= 0.15 L C=0.3 M pH= 7.9 pKa= 7.2 MW Na2HPO4=(23 x 2) + 1+ 95 = 142 MW NaH2PO4= 23 + (1 x 2) + 95= 120 …….. H2PO4- <–> HPO4-2 + H+ pH = pKa +log conjugated base/ acid 7.9=7.2 + log Na2HPO4/ NaH2PO4 0.7= log Na2HPO4/ NaH2PO4 1) Na2HPO4/ NaH2PO4 = 5.011 2) Na2HPO4 +...
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