Recent content by blumatrix

so velocity will be 0 at the peak after the engine dies... setting V = 0, and using Y(final) = Yi + Vi(t) + 1/2at^2 Yf = 0 + 0 + 1/2(5)(23.52^2) Yf = 1382.98m is that right?

initial velocity can be 0 if the object is not in motion, right? and 5 m/s^2 is the acceleration of the rocket.

?: A rocket is fired up at 5 m/s^2. After a certain time, the engine fails and the rocket goes into freefall. It hits the ground 12 seconds after engine failing. Find V(final) and height that the rocket reaches. the the way down... Vf = Vi - at set Vf = 0 b/c when it hits the ground, V =...