Recent content by BMath

Yes thank you very much for the help!

Ah yes I see it So if I have x+y 1R2 1+2=3=3.1 and y+z 2R7 2+7=9=3.3 then x+z 1R7 1+7=8=3.k we see that there's no integer k so that 3k=8 thus the relation is not transitive So if its wrong I only have to give a counterexample? And if its true you need to prove it

but then its always transitive cause i can't find any false relations 3R6 and 6R9 x+z=24=3*8

x,y,z are integers. xRy and yRz 0R2 and 2R5 0+2=2=3k and 2+5=7=3k we see that there doesn't exist an integer k such that 3k=2 and 3k=7 so xRz doesn't exists.

That x+z is not an integer?

I don't understand it really I read my textbook over and over but I still can't imagine how it works

Yes and this is my proof: Reflexive: x+x= 2.x and not 3.x so its not reflexive Symmetric: x+y = 3k so y+x = 3k Transitive: xRy and yRz x+y=3k for keZ x+y=3n for neZ So x=3k-y and y=3n-y so x+z=3k-y+3n-y= 3(k+n)-2y We see that its not transitive Because it hasnt al three properties it isn't an...

Hey, Ive a question in my textbook and I don't really know what to do! The question is: I know I need to prove that the relation is 1)Symmetric 2)Reflexive 3)Transitive But how do I prove this