Recent content by Bo-Chien Huang

Ok, I get it.

From ##i \hbar | \dot \psi \rangle = H | \psi \rangle = (H_0 + i T)| \psi \rangle##, we know ##| \dot \psi \rangle = \frac{1}{i \hbar} (H_0 + i T)| \psi \rangle## as well as its dual ##\langle \dot \psi | = \frac{1}{-i \hbar} \langle \psi |(H_0 - i T) ##. Directly consider ##\frac{d}{dt} \langle...

Hi, my name is Bo-Chien Huang. This is my 1st time to join in such a forum. I'm pursuing a physics master's degree, and I want to improve my problem-solving skills.