Recent content by Bo_

I can see clearly now the rain is gone, thanks.

ok thanks, so assuming it's right, do set equal to y, then zero? In other words: 0 = (3x^2 - 1) / 2 and then quadratic formula using that^^^^? (remember I'm trying to find all slope zero tangent lines of the original equation.) If my procedural thinking is correct, then I don't think I need...

The problem is to find the horizontal tangent lines of an equation. Here's my attempted differentiation. y^2 = x^3 - x + 1 {dy/dx} = (3x^2 - 1)/(2y) Correct, or no? i'm going to need more help going forward even if that is right, I just want to make sure it is.

I don't know but that'll have to do. There doesn't seem to be another way.

Homework Statement P is profit in dollars of a particular mp3 player. P = -76x^3 + 4830x^2 - 320000, 0 < x < 60 x is ad expense (in tens of thousands of $.) Find the smaller of two ad amounts that yield a profit of $2,500,000. The attempt at a solution All I can do is get...

Okay so they're 6, +1/2, -1/2. Correct if I'm wrong. If not, thanks.

Damnit, yeah I meant to have (x - 6).

k, so I factored it to (1 - 4x^2)(-x - 6) ...what are the zeros? 6? Someone help me interpret that...pleeease.

Homework Statement Find the zeros of the function algebraically. Homework Equations f(x) = 4x^3 - 24x^2 - x + 6The Attempt at a Solution If all quantities had an x in them, I'd just factor out and x, and treat it as a quadratic. But that freaking 6 is ruining my plan and I'm stuck.