Recent content by Bob Kutz

Steve, "The imaginary part of i" is an odd construct and a mis-use of what I said. In Euler's Identity, there is no imaginary part at all in the solution. e^ipi + 1= 0. It certainly does not equal 0+i. So you've misread what I said or misunderstand the discussion. Again and for clarity...

Hootanany; I did mistate when I said the 'value of i is zero', it probably should've read 'the coefficient of i is zero', or 'the imaginary part is zero' or something. That would've been clearer to my point. Point of fact; the imaginary part of the solution to e^iPi is in fact zero. It is not...

I am sorry. I had looked at Euler's as a trig function where i doesn't seem to have much of a role. Had I looked at it as literally the limit of (1+zi/n)^n, nothing else besides i works at all. Again, sorry for my narrow view of the topic.

I have a difficult time seeing how e^(2ipi) = 1. Are you saying e^((2pi)i)? I think that would be a bit different from simply replacing i. That is changing the coefficient of the angle. If you are truly replacing i with 2i then that would be equal to cos(pi) + 2i(sin(pi)), would that...

No; my original point is that the value of i in the equation itself is Zero, since it is multiplied by the sin of pi, which is zero; so you can replace i with anything you want to without effect. There is no i coefficient to the number, so it is no longer complex and resolves to a real number...

Well, that's technically true; but by defining your y-axis to match, it still works perfectly; and my original point is that i itself is completely irrelevant to the identity in that the sin of pi=0, therefor there is no complex component and the equation resolves as a real number. But...

Uhm, excuse me, Mr. Nebuchanezza, but the term i is defined as the imaginary unit. So labeling it as imaginary isn't really nonsense at all. So maybe it isn't me who should be banned. I never said that Euler's identity was wrong or didn't have practical value, I just pointed out that it...

Has anyone else noticed that if you replace i with (insert whatever imaginary meme you chose here), the equation works just the same; Try smurf for example; e^(smurf*Pi) = -1 Or Pterodactyl; e^(Pt*Pi) = -1 As long as e^((Really Imaginary Constant)*Pi) = cos (Pi) + RIC sin (Pi), then...