Excellent, thank you! Good hint.
The formula I have (that seems to work) is
SmallRadius = \frac{LargeRadius \sin 60}{1 + \sin 60}
If you paste the following into an html document, you can see it in action.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"...
Hello everyone!
I'm trying to find out how to precisely construct three congruent circles inside a larger circle, each tangential to both the outer circle and the other two circles. For example:
http://img4.imageshack.us/img4/1044/verybasicdrawing.png
An image I found on the internet...
Yes, that's what I mean by the magic constant.
Yes, I know that, but I'm trying to derive the formula from the series to prove that that is correct.
BF
Hey all. I'm trying to convert a series which gives me the magic constant for a magic square into an equation. How would I go about doing this?
The series is:
\mbox{S}=\left[ \frac{n+1}{2}+\left( n-1 \right)n \right]