Recent content by boomer77

...but it is wrong, and i don't know why

ok so for part d i have to find the maximum height the ball will reach in this case so my work will be: vf^2=vi^2+2ad 0=12.75^2+2(-9.8)d -162.6=-19.6d divided by -19.6 d=8.29 8.29+1.81 d=10.01

v^2=162.64 v=12.75

this is my new work -1.81=vsin48(26.9/v)-4.9(26.9/v)^2 -1.81=19.9-(3545.7/v^2) -21.8=-3545.7/v^2

wait nevermind i didn't make that negative

so here's my new work: d=vit+1/2at^2 1.81= vsin48(26.9/v)-4.9(26.9/v)^2 1.81=19.99-(3545.7/v^2) -18.1=-3545.7/v^2 v^2=195.9 v=13.99 my problem set is saying this answer is wrong, is there a flaw in my math?

that dy = 1.81 or is it negative?

i mean dy=1.81 (whoops

dx=18 vx=vcos48 t=26.9 dy=0 viy=vsin48 a=-9.8 then use d=vit+1/2at^2?

ok so for part b my answer is now 4.47 for part c my problem should look like this

ohh i get it my problem will be 3.55^2+x^2=5x^2! then solve for x!

so is this 3.55 one component?

but isn't that 3.55 my answer?

this equation that you wrote 17.8^2+3.6^2=(5x3.6)^2 what is it? I'm pretty new to physics (i started taking physics a this trimester at my high school) could you explain how to solve it?

i did do that and my answer came up as 3.55 (rounded) but my problem set is still saying it's wrong. where is my error? vf^2=vi^2+2(-9.8)(-16.01) (5vi)^2=0+313.8 25(vi^2)=313.8 313.8/25= 12.6 vi^2=12.6 vi=3.55