Recent content by Boon28
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Electric field of a charged nucleus (sphere) Gauss Law
hmm so for no. 2: integral of E.dA = Q/epsilon-zero solving the integral and rearranging, I got q(r) = Qr^2/(r^2+R^2).. for no. 3: charge density i was told i can get by finding the derivative of q(r) with respect to r. and so i got rho(r) = dq/dr = 2QrR^2/(r^2+R^2)^2 Do those seem reasonable?- Boon28
- Post #10
- Forum: Introductory Physics Homework Help
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Electric field of a charged nucleus (sphere) Gauss Law
I don't really get how to do the 'divergence' thing. Can u explain it in a simple way? P.S I'm not warrior_1 :/- Boon28
- Post #9
- Forum: Introductory Physics Homework Help
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Electric field of a charged nucleus (sphere) Gauss Law
hmm ok.. so where the question is concerned... 1. could it be that because the model assumes that where Gauss's law is used, 2 Gaussian surfaces are separately used and calculated with total charge enclosed over the 2 surfaces still being Q, and hence the (r^2+R^2) instead of just r^2? if that...- Boon28
- Post #3
- Forum: Introductory Physics Homework Help
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Electric field of a charged nucleus (sphere) Gauss Law
ok guys.. this question is regarding a spherical nucleus with radius R related to Gauss's Law... so where the electric field given as the following: E(r) = Q/4*pi*epsilon-nought(r^2+R^2) 1. the questions asks "why this model/behaviour for r>>R might be "reasonable" 2. what q(r) is needed...- Boon28
- Thread
- Charged Electric Electric field Field Gauss Gauss law Law Nucleus Sphere
- Replies: 9
- Forum: Introductory Physics Homework Help