Recent content by boris1907

for first particle \[s_1 = ut_1 - \frac{1}{2}gt_1^2 \] for second particle \[s_2 = ut_2 - \frac{1}{2}gt_2^2 \] we know that \[t_1-t_2=1 , t_2=t_1-1\] then \[s_2 = u(t_1-1) - \frac{1}{2}g(t_1-1)^2 \]. since they meet, s_1 should be equal to s_2. \[s_1 = ut_1 - \frac{1}{2}gt_1^2 =...

Given parametric equation implies that y=6x^2 -2 , then you should use arc length formula: L=\int\limits_a^b {\sqrt {1 + [f'(x)]^2 } dx} where f(x)=y=6x^2-2, a=0, b=\sqrt5 , f'(x)=12x L=\int\limits_0^{\sqrt 5 } {\sqrt {1 + 144x^2 } dx} ,after x = \frac{1}{{12}}\tan \theta substution...