Recent content by borobeauty66

Therefor torque = 94 N x 2.0 m = 188 N m. Will I need inertia for the next step?

Homework Statement A rotating disk of radius 2.0m (the mass on the disk, assume is negliable) with 4 points of mass each spaced 90 degrees apart from each other, each weighing 19kg. Each is position 0.2m from the axle. Inertia of the disk is 3.04 kg m^2 Angular Speed is 310 rad/s Torque is...

Force is applied tangently, to the rim, therefore at the 2.0 m. Ignore the mass of the disk.

The disk radius is 2.0m, the masses are at 1.9m from the axis.

Homework Statement I'm trying to caluclate the angular freequency, given that I've only been given various values for the problem. Radius 2.0 m, Force applied for 5 s = 94 N. 4 objects each at 90°, each weighing 19kg, and at 1.9m from the axis. From this, I've calulated the values of...

ah ok! thats what confused me, i thought they were different. :-P

What I meant by saying the equation was wrong was in your #3 post you put the equation wrong. In actual fact the mass should come after the division. Thus and not which would make k = 4Gπρ and not k = 4Gπρm Surely this means the m isn't canceled out at the end?

Ah ok. So final equation is t = 2π/(√4Gπρ/3)/m Still not sure how I can simplify this but thanks.

This is the original equation. I'm now wondering if F = -k x is infact equal to the above?

What I mean is the equation give at the start is F = -(4Gpi p/ 3) m r r^ It's not that included in the brackets. So I suppose it's not included in the value of K

Just realized that mass isn't part of the 4Gpi p/3 equation, it comes later. :-P

Anyway, I think I got it from here (minus simplifying it) Many thanks for your help!

Now, there's a challenge!

OK, so, k = mω^2 ω = 2π/t = √k/m 2π/t = √k/m makes t=2π/√k/m So replacing k t = 2π/√(4Gπρm/3)/m

So, F = -k x -k = F/x That makes -mw^2 = f/x -w = square root of f/x +m Am i going in the wrong direction?