Again, this may just be my stupidity but I thought I had already seen what happens when A becomes large by using the value 10^5? I can see that the closer my value of V- is to V+ then the higher the value of gain A is? I just don't understand how I am supposed to calculate Vin without an actual...
So if I just give the gain a practical value such as:
A = 10^5
Then use this value in:
Vin = 1.694118 - (2.4/10^5)
Vin = 1.694094
Vin is now less than V+ but only by a very small amount but this is still enough for Vout to be at its high limit. Is this more accurate or am I still going in...
Hi guys, I too am struggling to get my head around this question and was wondering if you could see if I'm on the right path to my final answer and give me a bit of guidance if I am way off.
My attempt so far:
Vout = +2.4V
Rf = 2k ohms
R1 = 4.8k ohms
Vin = ?
First I calculated V+ by using...