Recent content by boxybrownmd

To write expressions for the x and y components, would I just move the y to the left hand side and get the expression for just y, and then do the same for x?

Here is what I have so far. Is this the right process? https://scontent.fewr1-1.fna.fbcdn.net/v/t34.0-12/14344135_1254552687902440_1826194822450464519_n.jpg?oh=dc4822bd9ff309ed6c57b7d5d10a611b&oe=57D97E88

I sincerely do not know. I thought the distance between q1 and q3 was just SQRT((x^2) + (y^2)).

https://scontent.fewr1-1.fna.fbcdn.net/v/t34.0-12/14264093_1254405171250525_3984730770686346342_n.jpg?oh=346e65c981cd752be738e3496319668d&oe=57D9DCD3 This would be the magnitude of just F1, correct?

Yes I have, but this just seems more complex with two different forces.

Ok, I understand what you mean now. So basically, rather than find an equation that just finds distance for 6.9x10^-5, I need to find one that works for any net force to find a specific value of y? The only issue now is trying to figure out how to find an equation that would work from what I...

Ok, so I had something somewhat similar drawn when I first attempted the problem a few days ago. However, breaking it down is giving me a few issues. F1 and F2 represent the total force of particle 1 and particle 2. When you take both of the x components of F1 and F2, they will cancel out...

I do not understand what you are trying to say in post #15. The reason why I said Fy = 3.45 x 10^-5 is because the problem states that particle 3 experiences a force from particle 1 and 2 equal to 6.9 × 10^−5 N ȷ^. I assumed that j^ represented force acting in the y direction, and got 3.45 x...

Wouldn't the expression for net force just be SQRT((Fx)^2 + (Fy)^2)? Fx would become 0, Fy would be 3.45x10^-5?

I feel like this does not help me find the answer... I still don't understand exactly what this will do for me. It just winds up being the original net force I started with and the x forces canceling...

From this point is where I am lost then...

Wouldn't the charges exerted on Particle 3 from 1 and 2 just be opposites but equal? For example, if Particle 1 exerted 1 N of force to the right, than particle 2 exerts 1 N to the left.

I attempted to draw the diagram, but I do not understand anything else about the problem. I know that both of the charged particles (1 and 2) exert force on particle 3 in mirrored directions, which causes Fx to cancel but Fy to remain. However, in order to calculate F, you still need to know...

https://scontent.fewr1-2.fna.fbcdn.net/v/t34.0-12/14344969_1253913204633055_3281124858787924149_n.jpg?oh=6d016711bbcdadc3abae4e72aef365df&oe=57D9162B Edit: Forgot the picture :) I have attempted this but I am still lost on where to progress... I feel still at a loss on how to progress at this...

Well the issue is that I cannot draw it exactly since I do not know where the third particle technically would be?