Recent content by Boyle22

I think I'm heading down the right track with the Cubic function thanks to arildno but I can't figure out the coefficients. Anyone else out there that could help?

I can't figure out the coefficients. :( I know this is just algebra and I should know it, but how do you solve for the 4 unknowns(a,b,c,d) with only the 2 equations(Fx,Fy)?

Yes I understand. After I solve for all the coefficients a,b,c,d,e,f,g(still working on it) isn't there other criteria that must be met? Since you just set all the partials to 0 at the points of interest that just tells you they are critical points. From there they could be max's, mins or saddle...

Ok so the function has to be a cubic? Forgive me for being slow, I'm having a hard time understanding what's going on lol.

Sorry for not being clear. I need a max at f(1,1) and a min at f(-1,-1).

I am a bit confused with how you came up with that equation. I need a function of two variables (x,y)... I think? Something similar to this : f(x,y)=(x^2)(y^3)-(x^4)(y^6)+1/2(x^4)(y^6) Thanks for your help.

This is a calc 3 problem dealing with partial derivatives in 3space: I know that for a function to have a max at a specified point (a,b): Fx(a,b)=0 Fy(a,b)=0 D>0 where D=Fxx(a,b)Fyy(a,b)-[Fxy(a,b)]^2 D can not equal 0 Fxx(a,b)<0 For a min at specified point: Fx(a,b)=0 Fy(a,b)=0 D>0...