Recent content by Brad_

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    MHB How to calculate center coordinates of two reverse arcs in 3D space

    ok, then I did the following $$k=\frac{Q2-Q1}{||Q2-Q1||};l=\frac{Q1-Q2}{||Q1-Q2||}$$ $$c2=\frac{u+k}{2};c1=\frac{v+l}{2}$$ $$e=P1.u;r=\frac{e-Q1.u}{c2.u};C2=Q1+r*c2$$ $$e=P3.v;r=\frac{e-Q2.v}{c1.v};C1=Q2+r*c1$$ $$e=P1.c2;r=\frac{e-Q1.c2}{c2.k};M1=Q1+r*k$$...
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    MHB How to calculate center coordinates of two reverse arcs in 3D space

    At first step I did the following $$Q1=P1-s*u ; Q2=P3-t*v$$ where $$u=\frac{P2-P1}{||P2-P1||} ; v=\frac{P4-P3}{||P4-P3||}$$ and s,t are parameters for how far the points lies. Then I can not figure out how the parameters s,t behave. Is it right way how to define the first step?
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    MHB How to calculate center coordinates of two reverse arcs in 3D space

    I would rather see more detailed procedure how the result was computed then the actual result at least. I want to implement this as piece of code in 3dsmax script. I need to have the rays connected with two reverse arcs becuse then I will divide the arcs into several pieces of the same length...
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    MHB How to calculate center coordinates of two reverse arcs in 3D space

    Can you list here all the initial equations please?
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    MHB How to calculate center coordinates of two reverse arcs in 3D space

    Hi, Given 3D points P1(200,60,140), P2(300,120,110), P3(3,0,-1), P4(-100,0,-1) and the radius of arc C1MP3 is equal to radius of arc C2MP1. How do I calculate coordinates x, y, z of points C1 and C2? Points C1 and C2 are centers of two reverse arcs which are tangent to each other at point...
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    How to calculate center coordinates of two reverse arcs in 3D space

    Hi, Given 3D points P1(200,60,140), P2(300,120,110), P3(3,0,-1), P4(-100,0,-1) and the radius of arc C1MP3 is equal to radius of arc C2MP1. How do I calculate coordinates x, y, z of points C1 and C2? See this image. Points C1 and C2 are centers of two reverse arcs which are tangent to...
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