Recent content by bradsmith

V= √(2gh) sqrt(37^2-2*9.8*47)=21.16 Thats what I wanted not ag and i was lazy and didnt change my F

Homework Statement A baseball is hit directly upward with an initial speed of 37 m/s. Find the velocity of the ball when it is at a height of 47 m. Homework Equations F=ma F=ag The Attempt at a Solution F=(37)(-9.8)=-362.6/47=7.7[/B]

NVM I got it. F=ma F=14kg*3.4m/s2 F=47.6 Thanks everyone.

Let me start over. Three blocks rest on a frictionless, horizontal table (see figure below), with m1 = 6 kg and m3 = 14 kg. A horizontal force F = 111 N is applied to block 1, and the acceleration of all three blocks is found to be 3.4 m/s2 all 3 blocks are side by side F--->123 (a) Find m2...

Yes it force is applied to 1 and is in order as 123. so that means add all 3 6+12.64+14+32.64 f/m=a 111/32.64=3.4 so its 32.64? Im not sure why I did it that way. I thought because I only needed 2 and 3 that was the way to do it.

Ok F=(m1+m2+m3)xa 111=(6+m2+14)X3.4 111=(m2+20)x3.4 111=3.4m+68 111-68=3.4m 43/3.4m=12.64 is b 90.57 F=a(m2+m3) F=3.4(12.64+14) F=90.57 Thanks for not giving me the answer, I learn better by doing it. I think I did something wrong again

So I was sick last week for 3 classes and I really missed something and don't know what I am doing. Three blocks rest on a frictionless, horizontal table (see figure below), with m1 = 6 kg and m3 = 14 kg. A horizontal force F = 111 N is applied to block 1, and the acceleration of all three...