Recent content by BrendanM

The question is : Find an F(x) where fprime(-1) = 1/2 , fprime(0) = 0 and fdoubleprime>0 if it doesn't exist prove why. I cannnot explain it that well but here i go, i feel there is no equation that can be made for this. For an equation for be concave up on all intervals it must be in the...

so showing that a= 1/(4-4b) a= (4b-1)/4b gotten from a(1-b) =1/4, b(1-a)=1/4 only intercept once shows that there is no where that this is true

thanks for the quick response guys!

first problem : Let A and B be postitive numbers. SHow that not both of the numbers a(1-b) and b(1-a) can be greater than 1/4. second problem : Find a function f such that fprime(-1) = 1/2,fprime(0) = 0 and f doubleprime (x) >0 for all x, or prove that sucha function cannot exist. thanks...

Use the identity for tan(x-y) = [tan(x) - tan(y)]/[1-tan(x)tan(y)] to show that if two lines L1 and L2 intersect at angle theta then tan(theta) = m2-m1/(1 + m1m2) where m1 and m2 are the slopes of L1 and L2 respectivly. hmm ihave no idea where to start for this it doesn't make sense to me...

yah felt kinda silly by asking for help on #2, well for anyone who was wondering...for #1 my prof was wrong. He said he made a mistake after i confronted him about the two values.. Oh well sounds good. ty everyone that helped

If anyone can help I am in major need :|

I kinda have a question and an answer check... well here's my check. Let f(x) = x^2 + x. For any readl number a, let Ty be the y-intrecept of the tangent line to f(a), let Nx and Ny be, respectivly, the x-intercept and y-intercepts of the normal line to f(a). SHow that a = 0 is the only value...

wouldn't the answer be y = sqr(1-cos^2(x)) im really really sick right now... so I am going to bed, ill check this out in the morning, i hope i am well for school :| thanks

hmm ill think about this for a minute, thanks for help. hmm what do you mean by use trig identity

cool ill stay up for a bit, I am still working on it !

nm I am wrong

damn I am rusty, i thnk i got it... y= sqr(2^2 -x^2)/2 correct me if I am wrong

After working hours on my first assignment LOL (i really want to do good in school) i hav ebecame stumpted. The question is: A ladder, 2 meters long, is standing flat against a vertical wall. The foot of the ladder is pulled away from the wall. As this happens, the top of the ladder stays in...

help me please! Im very rusty here's my problem, please help thanks! The radius of a sphere is expanding at the rate of 1 meter/min. At t=0 the radius is 1. In earch case, find the requested function and sketch the curve. a)The surface area of the sphere as a function of the time; For...