Ok so here is what I did next:
-kinetic friction equals Tnet.
alpha=Tnet/I, so -mg(uk)R/(2/5MR^2) mass cancels 1 r cancels. -g(0.80)5/(2R) with the accel constraint ax=-alphaR, -g(0.80)5/(2) so alpha=at which equals -19.6 m/s^2.
I used kinematics after this to solve delta t...
3. A solid rubber ball is thrown so that it has an initial horizontal velocity of 12 m/s on a flat horizontal concrete surface, but is not initially rotating. Eventually friction will induce the ball to roll without slipping. Assuming you can neglect rolling friction, a) determine the amount of...
1. There is a figure showing two thin beams joined at right angles. The vertical beam is 15.0 kg and 1.00m long and the horizontal beam is 25.0 kg and 2.00m long.
Part a) askes to find the center of gravity to the two joined beams, taking the origin at the corner where the beams join...