In a real programmin glanguage you would use:
totalArea=0;
for (int i =0; i<100; i++) {
// set values of leftY, rightY, leftX and rightX here
// Note that their values are based on the current value of i
totalArea=totalArea+0.5*(leftY+rightY)*(leftX-rightX);
}
First time poster, long time reader...
Consider the truss bridge as shown in the attached diagram (Each member is the same length) A force of 1000N is applied 3/4 of the way across the bridge. We get:
R1 = 250 N
R2 = 750 N
Resolving from the left we get:
T1 = 250 / sin 60
T1 sin 60...