Recent content by BridgeBuilder

In a real programmin glanguage you would use: totalArea=0; for (int i =0; i<100; i++) { // set values of leftY, rightY, leftX and rightX here // Note that their values are based on the current value of i totalArea=totalArea+0.5*(leftY+rightY)*(leftX-rightX); }

How about y_out = y_out + (0.5 * (y_right + y_left) .* (x_right - x_left)); Remember to set the initial value of y_out as 0 though.

Couldnt you use the following? (I know nothing about MATLAB but I know programming) y_out += (0.5 * (y_right + y_left) .* (x_right - x_left));

First time poster, long time reader... Consider the truss bridge as shown in the attached diagram (Each member is the same length) A force of 1000N is applied 3/4 of the way across the bridge. We get: R1 = 250 N R2 = 750 N Resolving from the left we get: T1 = 250 / sin 60 T1 sin 60...