Recent content by britt

[b]1. The problem A velocity selector consists of a parallel plate capacitor placed in an outside magnetic field (see figure). Charged particles entering the velocity selector experience an electric and a magnetic force (neglect effects due to gravity). Given is the setup in the figure below...

1. It is desired to determine the magnetic field of a bar magnet. The bar magnet is pushed through a 10.0-cm diameter circular coil in 2.50 × 10-3 s and an emf of 0.750 V is obtained. Find the magnetic field of the bar magnet. [SIZE="3"]ε = 0.750 V d=0.10 m t=2.50x10-3 s [b]2...

C) ε2-(i4 / r4 + i3 / r3) +ε1-ir=0 d) p= iv = (i+(i3 + i4))(ε1+ε2) e) none would change assuming r2 and r5 have the same resistance

I34=I3I4R3R4 / R34 I3=I4 Not sure about how to relate them I = I3 + I4 ?

help!

C) don't all currents go like _____> | | | ^ ^ | | | | <___V

The potential difference across both are equal?

1/R3 + 1/R4 = 1/R34 -- does this have anything to do with it?

R3i3=R4i4

A) yes I assigned an I to each 5 resistors. Would the series ones be the same? R1 R2 and R5 B) I3=I4 so I34/2

[b]1. You are part of a team designing a go-cart. A member of the team has given you a picture of the lighting for go-cart. Your mission is to analyze the circuit. The team has not yet decided on what lights or batteries to use yet, so you need to do the analysis using variables (into which...

E= σ/2ε0

Is the electric field value just 0 then? or do i add the electrons charge to 0

or does that just cancel out?

The gravitational field would be going down correct?