When we expand the vector triple product, we get a linear combination of the vectors inside the cross product whose coefficients are in the form of dot product.
I know, and that is the very thing I fail to understand.
Can we instead say that the atmosphere applies a pressure through the seal? And, is the same thing applicable in this question?
After we seal the tube, the tube, the pressure above the mercury due to the gas is 1 atm cuz the concentration of gas remains the same and we do the same steps as in...
I do not get this part.
How do we find that out?
Sorry, I did it due to time constraints, I shall take care from next time.
Could you please confirm if I am correct here, after I split the terms ##\vec v_r## and the term ##\vec \omega \times (\vec x_i - \vec x_r)## with the vector product, I...
I meant the no. of molecules that can apply the pressure on the surface of the water, sorry for the poor wording. Initially, all the air above the water surface will apply 1 atm on it. But after the container is sealed, the air molecules above the seal do not apply any pressure on the water...
I do know how to solve this question:
We find the equilibrium pressure due to air molecules inside the container (after water has stopped flowing). Then, assuming initial pressure of gas inside the container to be atmospheric pressure, we use Boyle's law to find the new volume of the gas and...
I understood that, but my doubt was how we would know the radial velocity of the object with reference to the reference point. Or do we not need it as it is not needed for the calculation of the angular momentum vector?
Okay, I shall try it.
Got it, but how will it help to solve the problem...
I didn't get the 1st line. ##\vec v = \vec v_r + \vec \omega \times (\vec x - \vec x_r)## How do we know whether or not the object moves radially to the reference point?
Also, I did not get how you obtained the 3rd line from the 2nd line.
I am not familiar with the term "moves inertially". Does...
I did that and got the correct answer, but that is not my question. My question is how to get the correct answer by taking the reference as the centre of the loop.