Thank you both for your replies.
Well it wasn't as easy as it should have been. Though I actually answered it within seconds of looking at it. My teacher simply wanted the question to test a different part of my ability. When I didn't do that, but got the right answer, I got 1 mark of a...
Thank you for replying.
The concepts you are discussing are calculus, and are far out of my humble reach. As impressive as your analysis is, it's not something I can relate to. It's certainly nothing I'd be expected to know at this stag, let alone apply.
Maybe in a few years... It's...
Thank you very much, both of you, for your help. I may interrogate my teacher for further information- but I feel that now I've got a firmer handle on the situation. This is solved.
And now that you've stated what rules you've used, I can actually sort of see how they apply. Regardless, I'm not at a point in my education where I'd be able to make this connection myself. Thank you again.
Thank you for sharing this.
Unfortunately this math is simply beyond me- though I can appreciate the effort. However, I'm now going to study logarithms. This method looks useful...
Thank you for replying.
I'm going to apologize again here, as I think the late hour is crippling me somewhat, but I'm at a loss as to how you found x=1/4^1/2 as the solution. I get how you found 4^x=1/x, as I simplified the statement to that point in my own attempt. I realize that at this...
Thank you for replying.
You might have missed it, or I was unclear, but I've already explained how I found the answer.
I set both sides of the equation individually equal to y, then using a graphics calculator (casio I think) graphed y = 2^x and y=1/sqrt x. I found the point where they...
Homework Statement
2x=1/ square root of x.
Homework Equations
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None that I feel ought to be included.
The Attempt at a Solution
To answer the question I graphed 2^x and 1/sqrt x individually. They intersect at an x value of 0.5, so x= 0.5.
The problem is that while the answer was...