Recent content by bruce550

got the answer.. tnks..

hey i think i have got it... chek dis.. tao=pEsintheta.. so sintheta=theta right?? alfa=qxetheta/mx^2=qetheta/mx now since theta=x/√l^2-x^2 ... so putting we get... alfa=qE/m√l^2-x^2

mmm.. do you mean a=dv/dt and w^2 *r=dv/dt ... if it is den.. how do i find ω here?? i know dat ω=v/r...

**rate of chng of tangential velocity

of course... its the rate of tangential velocity. ohk .. can you tell me to what parts i m corrct?? i mean i did dat domega/dt =(dq/dt)^2 *(k/mgx^2) .. and you are saying about centripetal acceleration.. :(

hhey... i m not getting your point.. can u jst solv it.. i mean if u knw d right way 2 solv it. tnks.

i mean i get domega/dt =(dq/dt)^2 *(k/mgx^2) ..

ohkay.. i did t. α=d(omega)/dt=d^2θ/dt^2 right? then ... using previous values from the first aprt of the question i get.. (dq/dt)^2 *(k/mgx^2) .. right? now to find the instantaneous speed .. how do i find the mass and x? thanks again.

i rly don't know how to attempt this part. serious!

yea gt dat... tnx. but what about the next part??

nd hi... :)

tcos(theta)=mg and tsintheta=F dividing we get tantheta=f/mg =(kq^2/x^2 )*1/mg ... - (1) now since theta is very small so theta=tantheta. equating 1... we get x^2=kq^2/mgtheta and hence we get the value for x .. m not sure if m correct. but if i m then how to find the second...

em waves constitutes both magnetic and electric field... howewever in vacuum a combination of mutually perpendicular electric and magnetic fields is refrd 2 s an emwaves... it components are E=E1SINw(T-X/C) AND B=B1SINW(T-X/C) .whr E and B are sinusoidally varying electri field and magnetic...

Help please...

If 2 similar pith balls of mass m are hung from a common point with the help of 2 long silk threads. The balls carry similar charges q. Assuming theta is very small find an expression for x. Also assuming that each ball loses charge at a rate of 1*10^-9 c/s at what instantaneous relative speed...