Recent content by Bry2323

Ok, I'll take a break and think it over, just trying to make sure I truly understand everything, you've been a big help, cheers!

I think I am confusing myselfs because I am thinking the only way the addition of 25m would need to be added was if the accelerations were the same, not sure why i can't grasp the idea, think I am just burnt out

ok perfect thank you, so what exactly am i saying when i say the displacement of car = displacement of truck +25.0 m, my brain is fried after today but I am having trouble understanding the theory behind it in lamens terms, my mind is wanting to think its the car +25 to make up for the deficit...

Ok well how do i move the 25.0 m to the right side without it being negative?

ok I think i got it but I think I've done way too many steps 2.20 m/s^2(t^2) +25.0m = 1.85 m/s ^s (t^2) .35 m/s^2(t^2) +25.0m = 0 .35(t^2) = -25.0s^2 t^2 = -71.43 s^2 t= 8.45 s

I really can't, is that a quadratic? It's been awhile since I have been in Algebra.

I think I had it correct underneath that? I really don't know how to simplify that last line if that is the correct formula

I'm not sure, are you pointing out that displacement of truck should be displacement of car + 25.0 m?

The truck starts in front. The displacement for the car is 0m and truck is 25m?

Sorry, didn't realize that until i searched around a little more. So far I have displacement of truck equals 1/2a x t^2 = 1.85 m/s^2(t^2) I am thinking displacement of car = displacement of truck + 25.0 m = 1/2at^2 I am left with 1.85 m/s^2(t^2) = 2.20 m/s^2(t^2) + 25.0 m?? This is where I am...

A truck and a car both start from rest at the same time on a straight track. The car is 25.0 m behind the truck at the start. The truck accelerates at 3.70 m/s^2 and the car accelerates at 4.40 m/s^2. How long does it take for the car to catch up to the truck? Hey all, first post, didn't think...