Recent content by BuckBee

It has been indeed! I just need to get the generator sorted, excited and producing

Hi the project is a wind farm simulation with 48v DC micro grid. The DC motor simulates the wind fan, the AC motor acts as the generator to produce about 100v AC. Its then rectified to DC and bucked down to 48v. The 12v DC battery is boosted up to 48v DC to provide power when there is no wind...

Here are a couple of good YouTube videos about the Self Excited AC Generator. These guys seem very excited and knowledgeable about it

Hi Baluncore thanks for the excellent detailed explanations. Its getting a bit too technical for me lol but I really do appreciate the help. You definitely know your stuff. I have the battery side sorted with a boosted 48v (see image) I just need to produce about 100v AC on the generator side...

Hi thanks for the reply and feedback. I have a rectifier to convert to DC then a buck converter to drop the voltage down to a consistent 48V The DC motor is 2500 RPM and the AC generator is 1350 RPM so sufficiently above synchronous speed I'm not sure abut the locked rotor. In YouTube videos...

Hi I'm doing a uni project and need help with a Self Excited AC Single Phase Generator. I'm using an AC Single Phase Induction Motor to act as the generator. Its turned by a DC Motor The AC motor is 1350 RPM and the DC motor is 2500 RPM Its not producing any electricity (just a few volts) for...

Great, thanks for the help, I think I've got it now. Can you please double check the calculations and answers and let me know if correct, Cheers

So does that look correct? If so I can then work out the x, y, z forces. Also how do I express the answer in cartesian vector form?

ok got it!

cool thanks but we don't know the distance DC to find out the length DG using Pythagoras

ok I admit I have no idea how to do the 3D x, y, z forces for CD. I have no idea what formula to use or where to start The 2D y, z forces for AB I understand that, see the calculations in the image attached below, I am sure that's correct

Thanks but I am still a bit confused with the (x) force. I am really not sure about the 3D calculations. The horizontal length for C to D is 2 meters with a Fc of 200N +y direction force is tan(1.5sin30/(1+1.5cos30) = X then 300 CosX -z direction force is tan(1.5sin30/(1+1.5cos30) = X then 300...