Recent content by cabron299

thanks a lot! i got the right answer (1/5) is this method trustworthy for most limits?

oh ok i need to remember the absolute value after x comes out of the sqrt.. so after i have the limits of all the four parts i can sum them up? thanks a lot!

1?( sqrt(x^2-x+1)/(x) simplifying [x*sqrt(1-1/x+1/x^2)]/x, the x´s cancel and I am left off with sqrt(1-1/x+1/x^2)= 1 right?

ummm... my teacher said conjugates were the best for limits with a sqrt involved, i don't think we are in the same page (i wasnt able to understand what you did... if u could clarify that would be great =)) thanks in advance

lim [3 + sqrt(x^2−x+1)]/[sqrt(9x^2−7x) −2x+5] x−>-infinity i know the conjugate of the nominator is 3-sqrt(x^2-x+1), but what is the conjugate of the denominator (or do i need to try some other method)? PS- I cannot solve this with deravatives b/c the teacher tols us not to