Recent content by Cait602

Homework Statement A baseball is thrown at 85 mph and is thrown with a spin rate of 125 rpm. The distance between the pitchers point of release and the catcher’s glove is 60.5 feet. How many full turns does the ball make between release and catch? Homework Equations Vf^2=V0^2+2a(Δ x) X=...

Ok, great! Thanks so much you guys! This really helped.

Well put that way.. I think block 2's final momentum would be 15 also because.. 10 Ns= -5Ns+ 15 Ns to make both of the side equal, which would be what needs to happen. So, block 2's change in momentum would be equal to block 1's, i think If it's ok, I'd like to ask another question, hopefully...

Ok that makes a lot more sense, so block 1 would definitely have a greater change in momentum out of the two since it changes direction and will have a loss of momentum, correct? So, if block 1 does not have conserved momentum, is the change in momentum in the left direction.. because.. the...

A) The forces would be equal but opposite in direction. B) I just meant that the sum of the force in the vertical direction=0 because of the lack of movement in the y direction, and so would not contribute to our net force. Our net force would ∑F= -Fcollision for block 1. C) And ah yes, I'm...

Homework Statement Block 1 collides with a stationary block 2, block 1 bounces back going in the opposite direction. I assume by this type of picture it means that block 2 also is going to the right because it's not saying it's at rest any further. A) Rank the horizontal forces in both of the...

I do... But we don't know what mass 1 is, so I was assuming that that isn't a certain 1/5, rather that mass 1 may be 15 kg or some mass divided by 5. But, I guess it's 1/5 then.

I mean m2 because m2= m1 /5 in the above problem.

v1, i / sin(30) = v2 If m1 was say like m1 /5 or something that didn't divide out as easily, can you show me what that type of situation would look like for future reference? Would I just end up with a mess of fractions? m1 would still cancel, but we would be left with everything else divided...

m1 (v1, i /2) = m1 /2 (v2 sin(30)) Math is not my strongest area, and neither is doing math with only variables.. Should I just leave it so.. if i divided the m1 /2 out of the right side.. on the left side m1 would cancel and the /2 would cancel with the /2 from the v1, i /2? I might still...

wouldn't we have to have only a velocity on one side to find the final velocity of ball 2? how would I solve for the ball 2's final velocity with the mass on that side with it? Was I correct up until that point?

Homework Statement Two balls move toward each other. Ball one is moving in the positive direction, has a mass of m1, and a velocity of v initially. While ball two has a mass of m1/2, is moving in the negative direction, and has initial velocity of v2. Once the collision takes place ball one...