Recent content by caityjo

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    Calculating Resultant Force: 60N East + 40N North | Magnitude & Direction

    I think I had my calculator in the wrong mode... sin(60/72)=.014 cos(40/72)=.999 tan(60/40)=.026 I think that's right? but what do I do now??
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    Calculating Resultant Force: 60N East + 40N North | Magnitude & Direction

    ok...so let me see if I get this... the opposite is 60N east right? and the Adjacent is 40N north. So... sin(60/72)=.740 cos(40/72)=.850 tan(60/40)=1.5 right?? and what part do I have to break down the angles into the x and y components?? I have been working on this ONE problem for...
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    Calculating Resultant Force: 60N East + 40N North | Magnitude & Direction

    I know how to do that part, I got the magnitude of R both graphically and using the pythagorean theorem...but I can't remember how to find the direction using trip...I know I have to break it down and stuff...but I don't remember how
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    Calculating Resultant Force: 60N East + 40N North | Magnitude & Direction

    But like, I know how to use them for the most part...I can find the magnitude ok, at least I think so...(72N right?) but the direction I can't get
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    Calculating Resultant Force: 60N East + 40N North | Magnitude & Direction

    Kinda?? I am just learning this stuff...and my teacher sucks, so I am kinda lost as to how I do this.
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    Calculating Resultant Force: 60N East + 40N North | Magnitude & Direction

    a force of 60N due east and a force of 40N due north act concurrently on an object. What is te magnitude and direction of their resultant? Find: Magnitude (graphically and using the pythagorean theorem) and the direction (graphically and triginomically) HELP! My brain is not working...I can...
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