Recent content by cak

Can someone help me understand this one? The problem is: Four beads-red,blue,yellow, and green-are arranged on a string to make a simple necklace as shown in the figure. How many arrangements are possible? The answer in the book is 3, but I don't get it. I thought it woud be a permutation...

wait...cant you find acceleration because you know that w=mg which means..70=m(9.8) m=7.1429kg and then f=ma 44=(7.1429)a and you find that a=6.15996 but i don't understand what you need acceleration for

Does the angel contribute to the applied force?? If not, wouldn't N=44+70?? Also, Dont you need mu first in order to find the force of friction for part b??

haha i feel dumb :) but that gave me the right answer so for part c do i say... 6826.454=(mew)(7.14)(9.8)(cos52)?

Need Help with "Work" P Can anybody help me w/ this question?? A flight attendant pulls her 70.0 N flight bag a distance of 252 m along a level airport floor at a constant speed. The force she exerts is 44.0 N at an angle of 52.0° above the horizontal. (a) Find the work she does on the...

thank you so much :)

Does that mean I am adding the unknown force to N?

ok well... correct me if I am wrong but... if acceletation is zero, then wouldn't that mean ma=Fparallel-Ffriction 0=32(-9.8)(sin35)-.2(-9.8)(32)(cos35) but how do i apply that to get the force applied to prevent the crate from sliding down?

Wouldnt that mean that the force of friction is equal to the parallel force? Doesnt that also mean that they're going in the opposite direction and their magnitudes are the same...

Since the crate is at rest... doesn't that mean that the acceleration has to be zero? so would that mean that the forces parallel to the incline would have to be zero...possibly??

Newtons second law tells us that acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. acceleration is directly related to the net force and inversely related to the mass...

F=ma ...that if the force goes up then the acceleration goes up? cause mass stays the same here.

do you mean like the µk (.2) * normal force has to equal 179.87? so like (the unknown force + the normal force of 257) * .2 = 179.87? is that right?

umm by increasing the normal force or µk?? I think this is right since the force of friction=µk*N Considering the fact that the force of friction is directly related to µk and/or the normal force. am i right? thanx for helping me!

Here is the problem I'm having trouble with... The coefficient of static friction between the 32 kg crate and the 35.0° incline of Figure 4-34 is 0.2. What is the minimum force, F, that must be applied to the crate perpendicular to the incline to prevent the crate from sliding down the...