I tried pairing momentum and energy equations together and solving in terms of v0 and v1. but the answer was incorrect
Kinetics:
.5m v02 = .5mv12+.5Iw2
where I=(1/12)MR^2
M=2m
and w= v2/R
thus mv02=mv12+(1/6)mv22
v02=v12+(1/6)v22
Momentum:
mv0=mv1+Iw
v0=v1+(1/6)v2R
With the R left i was unsure...
So this just popped in my head but i'd like to check if my idea is correct
M/V is a constant. Thus the velocity for the rod must be 2v1
Go back to the momentum equation
mv0= mv1 +2m*2v1
solve for v1
v1=1/5 v0
Thoughts?
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