ok i tried using this formula:
m1v1 + m2v2 = (m1 + m2) v(final)
m1v2 + m2v2 = (m1 + m2) times the square root of 2gd (gravity and distance)
then i isolated for v1 but i don't know how to apply the coefficient of friction to the problem...
Need help!
A 1.0x10^3 kg Toyota collides into the rear end of a 2.2x10^3 kg Cadillac stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.8m before stopping. The police officer, knowing that the coefficient of Kinectic friction between the tires and...