Recent content by caratacus
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Average distance in latitude/longitude cell using Haversine formula
Awesome. Thank you so much for you help!- caratacus
- Post #9
- Forum: Calculus and Beyond Homework Help
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Average distance in latitude/longitude cell using Haversine formula
Aha, thank you! That helps a lot; the integral has a reasonable amount of variation when I integrate with respect to different values of x and y. However, there still seems to be something wrong: NIntegrate[d, {y, 40, 45}, {x, 85, 90}] now returns 4650.41 km. This can't be the average...- caratacus
- Post #7
- Forum: Calculus and Beyond Homework Help
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Average distance in latitude/longitude cell using Haversine formula
Using the second version with arcsine instead of arctangent, x = 15; y = 10; d yields 7825.55km (distance from 10°N, 15°W to 42°N, 87.5°W...why I have x for longitude and y for latitude is beyond me). This is only a few km off of an online great circle distance calculator...- caratacus
- Post #5
- Forum: Calculus and Beyond Homework Help
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Average distance in latitude/longitude cell using Haversine formula
Thanks for the reply! Here's a short modification to the equation, then, using arcsine: radians = Pi/180; startLong = 87.5; startLat = 42.5; dlon = startLong - x; dlat = startLat - y; a = Sin[dlat/2*radians]^2 + Cos[y*radians]*Cos[startLat*radians]*Sin[dlon/2*radians]^2; c =...- caratacus
- Post #3
- Forum: Calculus and Beyond Homework Help
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Average distance in latitude/longitude cell using Haversine formula
Homework Statement I've constructed a 5°x5° latitude/longitude cell, from 40-45° N and 85-90°W. This puts the center somewhere near the southern tip of Lake Michigan. I'm trying to find the average distance from the center of that cell (42.5°N, 87.5°W) to any other point in that cell...- caratacus
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- Average Cell Formula
- Replies: 8
- Forum: Calculus and Beyond Homework Help