You were right though, its like a collision event between two heat sources, with Q lost being the total energy exerted by the system and the mass being the variable of interest.
Ok I see what I was doing wrong. I needed to take the Qlost, the heat expended, and set it equal to the total amount of energy which was MwCw(deltaT) + MeCe(deltaT). That gave me Mw=Qlost-MeCe(DeltaT)/Cw(DeltaT)
Thanks for trying though!
which is where I run into problems, when I assume they have equal initial temps then the answer is incorrect. The problem only states that the engine has an initial temp of 31, it doesn't specify the waters initial temp. You would think with the heat expended you could calculate it.
So we have m1 being the water that is holding heat when the engine is running. Then we have the m2 which is the iron engine holding heat until the engine is cooled. I don't see how I have known initial velocities though if I'm not given the initial temperature of the water. I know the amount of...
Homework Statement
Given the specific heat of water is cw=4180 J/kgC
A 241 kg cast-iron engine contains water as a coolant. Suppose the engine's temperature is 31C when it is shut off and the air temperature is 15C. The heat given off by the engine and water in it as they cool to air...