Recent content by Carlo2986

Your answer to 'At what load would you expect failure to occur?', Could'nt you have used the equation: Fc = σcA Fc being the axial load σc being the critical stress which will cause buckling A being the cross section area It gives the same answer and is a lot shorter. Or is it...

Also, your answer for 2c, shouldn't it relate to stress in the beam, and not the bending moment? The diagram looks correct but the numbers don't. I'm not an expert so any help would be appreciated :)

And this . .

Ignore this

OK, I see. I suppose only using numbers at the end reduces the chance for error througout the workings as well.

Unfortunately I'm not quite as gifted so I have to go the long way round just so it makes sense. When you use " ' " what does that mean?

So using the new Vmax Vmax = Aω 0.516 = 0.01ω ω = 0.516/0.01 ω = 51.6 ω = √(k/m) 51.6 = √(200/m) m = 200/51.62 m = 0.075kg Does that look correct?

I'm no expert so please don't take my answer as law, but I worked it out going back from the original Vmax of 0.258ms-1 You need to find the mass that will give you double your original Vmax which will be 0.516ms-1 I used equations Vmax=Aω and ω=√(k/m) Im sure someone could correct me...

How did you get acceleration to equal 12.551 m/s? Using w/md=a I got 13.33 m/s which ended up giving me 451.19J @ 0.92s which has already been pointed out to be too high a value for the KE. I can't see where I'm going wrong??