Recent content by caspar

Thank you, Dick, you've helped me a lot. caspar

the number of photons equals n = 1J/(f*h) so v_m = (2*n*h)/(\lambda*m_m) Well, the deflection measured on the level of the unmoved mirror is about s = 3,3667*10^-5m. I feel quite uncomfortable with that number. Is it likely to be such a number?

Ohh, so i can get the kinetic energy: v_m = (2*h)/(\lambda*m_m), which equals the potential energy at the maximum deflection. So the height of the vertical displacement is h = (v_m^2*m_m)/(m_m*g). Is that right?

Actually, my problem is to combine the Impulse with the amplitude of the oscillation. However, I've tried another approach: I assume that the energy the mirror gets is E = mc^2. I calculate the number of emitted photons, get m and receive E. Now, If I translate this Energy E into potential...

Hallo to all members, this is my first post. Homework Statement A short Laser flush with the Energy E = 1J hits a ideally reflecting mirror, with mass m_m = 2 * 10^(-5) kg . The light has a wave length of 696 nm. The mirror is hanging on a rope with the length l = 0,1m. Homework Equations...