Recent content by caws
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Proof of 1^3 + 2^3 + ... n^3 = [n(n+1)/2]^2 for Positive Integers
thanks, at least I know I am on the right track and was understanding the process, now all I have to do is solve to prove. :smile:- caws
- Post #5
- Forum: Calculus and Beyond Homework Help
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Proof of 1^3 + 2^3 + ... n^3 = [n(n+1)/2]^2 for Positive Integers
Ok. I am going to try to work this through again and post tommorow.- caws
- Post #3
- Forum: Calculus and Beyond Homework Help
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Proof of 1^3 + 2^3 + ... n^3 = [n(n+1)/2]^2 for Positive Integers
I am trying to prove by induction 1^3 + 2^3 + ... n^3 = [n(n+1)/2]^2 when n is a positive integer Let P(n), if P(1) then n^3 = 1^3 = 1 and [n(n+1)/2]^2 = [1(1+1)/2]^2 = 1 the inductive hypothesis is 1^3 + 2^3 + ... k^3 = [k(k+1)/2]^2 Assuming P(k) is true then prove P(k+1) is true...- caws
- Thread
- Induction
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Proving "If A U C = B U C then B = C" Without Drawing a Venn Diagram
thanks all.. and also to HallsofIvy to the suggestion of making some simple sets. I submitted my homework and with the assigned variables and I received all points for this problem correctly.- caws
- Post #9
- Forum: Precalculus Mathematics Homework Help
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Proving "If A U C = B U C then B = C" Without Drawing a Venn Diagram
If I assign these elements Set A = {1} Set B = {1} Set C = {2} then assign it to my problem A U C = B U C then B = C A U C = {1, 2} B U C = {1, 2} which makes A U C = B U C true But B does not equal C since 1 does not equal 2 Is there a way to prove this without assigning...- caws
- Post #4
- Forum: Precalculus Mathematics Homework Help
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Proving "If A U C = B U C then B = C" Without Drawing a Venn Diagram
I am trying to prove this as false. Let A, B, C be any three sets. If A U C = B U C then B = C. I can draw a Venn Diagram to prove this and I can assign values to the sets to prove it, but how can I prove without doing this? Also is the counter value A U C = B U C then B not equal to C? Can...- caws
- Thread
- Diagram Drawing Venn
- Replies: 8
- Forum: Precalculus Mathematics Homework Help